Inserting multiple array values in mySQL database

Question

I have two PHP variables, both strings:

$friendslist = \"2323443,7245,284683,345123,8456234,95432\"

$id = \"10288272\";

The structure of the t

Answer 1

$comma  = "";
$values = "";
$array  = explode(",",$friendslist);
foreach ($array as $friendid) {
  $values .= $comma."($id,$friendid)";
  $comma = ",";
}
$sql = "INSERT INTO UserLinks (User_1, User_2) VALUES $values"

Answer 2

You aren't initialising $frienduserarray as an array, so array_push doesn't work.

$friendarray = explode(",", $friendslist);
$frienduserarray = array();

for ($n = 0; $n < count($friendarray); $n++) {
      $friendidpush = "('".$id."','".$friendarray[$n]."'),";
      array_push($frienduserarray, $friendidpush);
}

Note that this seems to be complicating things to me. Why is the second array even necessary? Just use string concatenation.

$query = "INSERT INTO UserLinks (User_1, User_2) VALUES ";
$friendarray = explode(",", $friendslist);

foreach ($friendarray as $friend) {
    $query .= "('" . $id . "','" . $friend . "'),";
}

$query = substr($query, 0, -1); // remove trailing comma

mysql_query($query);

Answer 3

You are getting this error because you have not declared the $frienduserarray as array any where in your code. Just declare it

 $frienduserarray=array();

before the for loop. After that your code should look like

  $friendarray = explode(",", $friendslist);
  $frienduserarray=array();
  for ($n = 0; $n < count($friendarray); $n++) {
      $friendidpush = "('".$id."','".$friendarray[$n]."'),";
      array_push($frienduserarray, $friendidpush);
  }