I am trying to list all the files in the directory but how would you separate each of the files by a blank line? basically each file displayed by separated by a blank line? I am
Your loops are close. However, using a traditional bash for
loop with ls
is dangerous - what happens if your filenames contain spaces? An easy solution with awk
:
ls | awk '{ print $0 "\n" }'
Not sure how portable the options -d and -t are, but pr is ubiquitous:
$ ls | pr -dt
Note that any file names with an embedded carriage return will have an extra carriage return added in the output. (I believe that problem occurs with all of the solutions presented so far.)
For reference : http://www.cyberciti.biz/faq/bash-loop-over-file/
for f in /tmp/play/*
do
echo $f
echo
done
Edited as per comments making it simpler.
Here's one:
find -printf '%p\n\n'
A slightly worse (but more portable) one:
ls | sed 's|$|\n|'
A more convoluted one:
ls | while read f; do
echo "$f"
echo
done
And here is what you should not ever do:
for f in `ls`; do
echo "$f"
echo
done
EDIT:
And, as mentioned by Nija, the simple shell-only one:
for f in *; do
echo "$f"
echo
done
This one has the disadvantage that on many shells *
by default expands to itself, rather than an empty string when no files exist.
sed
one-liner (or one-char-er):
ls | sed G
Done.