How to split a string (using regex?) depending on digit/ not digit

Question

I want to split a string into a list in python, depending on digit/ not digit. For example,

5 55+6+  5/

should return

[\'5\',\'         


        

Answer 1

Assuming the + between 6 and 5 needs to be matched (which you're missing),

>>> import re
>>> s = '5 55+6+ 5/'
>>> re.findall(r'\d+|[^\d\s]+', s)
['5', '55', '+', '6', '+', '5', '/']

Answer 2

Use findall or finditer:

>>> re.findall(r'\d+|[^\s\d]+', '5 55+6+ 5/')
['5', '55', '+', '6', '+', '5', '/']

Answer 3

this one is simplest one :)

re.findall('\d+|[^\d]+','134aaaaa')

Answer 4

If order doesn't matter, you could do 2 splits:

re.split('\D+', mystring)

re.split('\d+', mystring)

However, from your input, it looks like it might be mathematical... in which case order would matter. :)

You are best off using re.findall, as in one of the other answers.