Array to string conversion error in PHP

Question

I have following code to backtrace the error ....but its

$traces = debug_backtrace();

foreach ($traces as $k => $v)
{
    if ($v[\'function\'] == \'include\         


        

Answer 1

You are not creating array properly

 $args .= $v['args'][$key];

You are creating a string.

 $args = array(); 
                if(isset($v['args']) && is_array($v['args']))
                {
                    $size = count($v['args']);
                    foreach ($v['
                    args'] as $key => $arg)
                    {
                        array_push($args,$v['args'][$key]);
                       // some of your code
                }

Answer 2

$trace = debug_backtrace();
foreach($traces as ...)

There's something wrong here. $trace is a Debug Backtrace array. While you foreach($traces) ... which seems undefined. And you append to $traces which is supposed to be a non-scalar to foreach it.

Just name your variables properly and make names different!

Answer 3

you begin with:

foreach($traces as $k=>$v) <- $traces here is an array

then you try to do

$traces.= "xxx" <- $traces here is handled as a string

i would rather define a $tracestr string for aggregating text content.