XSL to show parent as columns, with matching children as rows

Question

I am new to XML and XSL. I am trying to take a XML strings generated by our vendor software and translate it into Excel format. The XML can have repeating Rows that each have a

Answer 1

IIUC, you want to transpose the given table - rows to columns, fields to rows. The foilowing stylesheet shows how this can be done. For simplicity, this generates an HTML table - the adjustment for an Excel worksheet should be trivial.

XSLT 1.0

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/RpcData">
    <xsl:variable name="col" select="RepeatingFieldSet/Row"/>
    <xsl:variable name="row" select="RepeatingFieldSet/Row[1]/Fld"/>
    <table border="1">
        <!-- header row -->
        <tr>
            <th>Field</th>
            <xsl:for-each select="$col">
                <th>
                    <xsl:value-of select="@Index"/>
                </th>
             </xsl:for-each>
        </tr>
        <!-- data rows -->
        <xsl:for-each select="$row">
            <xsl:variable name="i" select="position()"/>
            <tr>
                <th><xsl:value-of select="@Nm"/></th>
                <xsl:for-each select="$col">
                    <td>
                        <xsl:value-of select="Fld[$i]"/>
                    </td>
                </xsl:for-each>
            </tr>    
        </xsl:for-each>
    </table>
</xsl:template>

</xsl:stylesheet>

Applied to your example input, the (rendered) result will be: