Regex to find a string after the last colon

Question

Here is some sample input:

<210>   DW_AT_name        : (indirect string, offset: 0x55): double
    DW_AT_name        : (indirect string, offset:          


        

Answer 1

This regexp ^.*DW_AT_name.*:\s*(.+)$ does the job as just tested on regexplanet.

Answer 2

String type = str.replaceAll(".*:(?=[^:]+$)", "");

Answer 3

Try the next:

public static void main(String[] args) {

    String text = 
    "<210>   DW_AT_name        : (indirect string, offset: 0x55): double\n" + 
    "<ae>   DW_AT_name        : (indirect string, offset: 0x24): long int\n" + 
    "<b5>   DW_AT_name        : int";

    Pattern pattern = Pattern.compile("^.*DW_AT_NAME.*:\\s*([^:]+)$", 
            Pattern.CASE_INSENSITIVE);

    Scanner sc = new Scanner(text);
    while(sc.hasNextLine()) {
        String line = sc.nextLine();
        Matcher matcher = pattern.matcher(line);
        if (matcher.matches()) {
            System.out.println(matcher.replaceAll("$1"));
        }
    }

}

Output:

double
long int
int

Answer 4

You need no regex for this:

String yourString = "<210>   DW_AT_name        : (indirect string, offset: 0x55): double";
String result;
if (yourString.contains("DW_AT_name")) {
    int lastIndex = yourString.lastIndexOf(":");
    result = yourString.substring(lastIndex + 1).trim();
} else {
    result = "ERROR"; // or handle this however you want
}
System.out.println(result);

Simply find the last : and take everything after that. Then trim it to remove leading and trailing whitespace.

I edited my question, it needs to also check for DW_AT_name. String split wont [sic] do that.

Just use contains, then. (edited answer)