Dynamic 2D array in typedef

Question

How do I get this to work? I am not sure how many invoices a customer will be assigned to and want to leave it dynamic. Please help.

#include 
#in         


        

Answer 1

A pointer to an array with two elements would look like this:

int (*array)[2];

but it would perhaps be easier for you to use a typedef first:

typedef int pair[2];
.
.
pair * array;

and you can allocate a large chunk to such a beast just in on go. If you have a C99 (or upwards) compatible compiler this would read like

array = malloc(sizeof(pair[n]));

Answer 2

You can change invoices to int** invoices and then allocate dynamically using malloc(). You can allocate a 2D array like this:

int** theArray;
theArray = (int**) malloc(arraySizeX*sizeof(int*));
for (int i = 0; i < arraySizeX; i++)
   theArray[i] = (int*) malloc(arraySizeY*sizeof(int));