So far this is what I have got.
import random
answer1=(\"Absolutely!\")
answer2=(\"No way Pedro!\")
answer3=(\"Go for it tiger.\")
answer4=(\"There\'s different
The easiest way is to use a while loop like so:
import random
while True:
answer1=("Absolutely!")
answer2=("No way Pedro!")
answer3=("Go for it tiger.")
answer4=("There's different ways to do this.")
answer5=("Definitely not")
print("Welcome to the Magic 8 Ball game-use it to answer your questions...")
questio = input("Ask me for any advice and I'll help you out. Type in your question and then press Enter for an answer ")
print("Shaking... \n" * 4)
choice=random.randint(1,5)
if choice == 1:
answer=answer1
elif choice == 2:
answer=answer2
elif choice == 3:
answer=answer3
elif choice == 4:
answer=answer4
elif choice == 5:
answer=answer5
print(answer)
restart = input("Would you like to try again? ")
if restart == "yes" or "y":
continue
else:
break
after the import line add while True:
indent the entire code to the while loop. then at the end go like this:
restart = input("Would you like to try again?")
if restart == "yes":
continue
else:
break
To explain further. Continue will jump back up to the top pass
would work as well. break
will exit the loop. good luck!
Try adding a loop like this to your code:
restart = ''
while restart.upper() not in ['NO', 'N', 'EXIT']:
# ...
# Your code here
# ...
restart = input("Would you like to try again?")
This is essentially initializing restart as an empty string. Then the loop is only going to start while restart != 'NO'
. At the end of the loop we're getting a new value from the user for restart
so that if they say 'no'
or 'n'
the loop won't start again.
There are lots of other ways to do this, such as the inverse where you could check to see if the user entered a positive answer ('yes'
or 'y'
) or putting a break
if they say 'no'
.
Hopefully this gets you started.