Multiple if statements under one code, with multiple conditons [duplicate]

Answer 1

It's because:

if word == "A" or "B":

isn't the same as

if word == "A" or word == "B":

The first evaluates (is word == "A") logical_or ("B")

So the first version always evaluations to true. Here's an example:

>>> X = "asdf"
>>> if(X):
...     print("hurray")
... 
hurray
>>> 

Answer 2

Give this a shot

exceptions = set("belize cambodge mexique mozambique zaire zimbabwe".split())
vowels = set('aeiou')
plurals = set("etats-unis pays-bas".split())

word, sentinel = "", "quit"
while word != sentinel:
  word = input("Enter the name of a country: ")
  if word == sentinel:
    continue
  male = word in exceptions or word[-1].lower() not in vowels
  plurality = word in plurals
  apo = word[0].lower() in vowels

  if apo:
    print("l'%s" %word)
  elif plurality:
    print("les", word)
  else:
    print("le" if male else "la", word)

Answer 3

use:

if word in ["belize", "cambodge", "mexique", "mozambique", "zaire", "zimbabe"]:
    print("le",word)

The problem here is that word==("belize")or("cambodge")or("mexique") is not doing what you think. There are lots of explanations of this around, but to get it to work, you either need to do what I have above or something like:

if word=="belize" or word=="cambodge" or word=="mexique":  # etc