PHP Extract numbers from a string

Question

I want to extract numbers from a string in PHP like following :

if the string = \'make1to6\' i would like to extract the numeric charac

Answer 1

You can use this:

// $str holds the string in question
if (preg_match('/(\d+)to(\d+)/', $str, $matches)) {
    $number1 = $matches[1];
    $number2 = $matches[2];
}

Answer 2

You can use a regular expression as such, it should match exactly your specification:

$string = 'make6to12';
preg_match('{^.*?(?P<before>\d{1,2})to(?P<after>\d{1,2})}m', $string, $match);
echo $match['before'].', '.$match['after']; // 6, 12

Answer 3

This is what Regular Expressions are for - you can match multiple instances of very specific patterns and have them returned to you in an array. It's pretty awesome, truth be told :)

Take a look here for how to use the built in regular expression methods in php : LINK

And here is a fantastic tool for testing regular expressions: LINK

Answer 4

You can use regular expressions.

$string = 'make1to6';
if (preg_match('/(\d{1,10})to(\d{1,10})/', $string, $matches)) {
    $number1 = (int) $matches[1];
    $number2 = (int) $matches[2];
} else {
    // Not found...
}

Answer 5

You could use preg_match_all to achive this:

function getNumbersFromString($str) {
    $matches = array();
    preg_match_all("/([0-9]+)/",$str,$matches);
    return $matches;
}
$matches = getNumbersFromString("hej 12jippi77");

Answer 6

<?php
list($before, $after) = explode('to', 'sure1to3');

$before_to = extract_ints($before);
$after_to  = extract_ints($after);

function extract_ints($string) {
    $ints = array();
    $len = strlen($string);

    for($i=0; $i < $len; $i++) {
        $char = $string{$i};
        if(is_numeric($char)) {
            $ints[] = intval($char);
        }
    }

    return $ints;
}
?>

A regex seems really unnecessary here since all you are doing is checking is_numeric() against a bunch of characters.