I have a release branch named release/X.X.X.X
which contains all feature branches I want to deploy to production. The release branch is made on top of master<
you can use –G ‘regular expression’ to meet your requirement
git log release/X.X.X.X ^master--no-merges -G ‘regular expression’
(include or exclude the specified commit)
The git log command provides two interesting options here:
--grep=<pattern>
Limit the commits output to ones with log message that matches the specified pattern (regular expression). With more than one--grep=<pattern>
, commits whose message matches any of the given patterns are chosen (but see--all-match
).When
--show-notes
is in effect, the message from the notes is matched as if it were part of the log message.
Hence --grep
lets you find commits that do contain some particular string or pattern. You want commits that do not contain (any or all) strings, so we move on to:
--invert-grep
Limit the commits output to ones with log message that do not match the pattern specified with--grep=<pattern>
.
(Incidentally, note that release/X.X.X.X ^master
can also be spelled master..release/X.X.X.X
. There's no machine-level reason to prefer one over the other—both wind up doing exactly the same thing internally—so use whichever you find more readable.)
The question title admits a slightly different answer, which could be useful to some people. A simple way to compare two branches by commit title only is to dump commit titles from each branch to a separate text file, and open these two files in a diff viewer:
git --no-pager log --pretty=format:%s master > log_master.txt
git --no-pager log --pretty=format:%s other > log_other.txt
meld log_master.txt log_other.txt
We first dump commit subjects from branch master
to the file log_master.txt
, then commit subjects from branch other
to the file log_other.txt
, and open them in the visual diff viewer meld (one alternative is kdiff3).