How to dismiss the Kivy pop-up via a Button?

Question

I have a pop-up created with Kivy, which contains 2 buttons. User can dismiss the pop-up by pressing outside of the pop-up area (auto_dismiss = True), or by clicking the \"No\"

Answer 1

Would something like this work in kivy?

on_press : root.dismiss()

Answer 2

Try this: on_press = self.popup.dismiss() in replacement of on_press = self.popup_exit.dismiss

Answer 3

Change on_press = self.popup_exit.dismiss to on_press = lambda: self.popup_exit.dismiss() because dismiss is a function and needs to be called when the button is pressed.

def exit_confirmation(self):


    # popup can only have one Widget.  This can be fixed by adding a BoxLayout

    self.box_popup = BoxLayout(orientation = 'horizontal')

    self.box_popup.add_widget(Label(text = "Really exit?"))

    self.box_popup.add_widget(Button(
        text = "Yes",
        on_press = ExitApp.exit,
        size_hint = (0.215, 0.075)))

    self.popup_exit = Popup(title = "Exit",
        content = self.box_popup,
        size_hint = (0.4, 0.4),
        auto_dismiss = True)

    self.box_popup.add_widget(Button(
    text = "No",
    on_press = lambda: self.popup_exit.dismiss() ,
    size_hint=(0.215, 0.075)))

    self.popup_exit.open()

Answer 4

You can solve this issue by a lazy function

on_press = lambda *args: self.popup_exit.dismiss()

This way, the lookup will occur only when the button is pressed and popup_exit is already in place...