Dividing 2 numbers returns 0

后端 未结 3 442
一向
一向 2021-01-28 06:48

I\'m trying to divide 2 counts in order to return a percentage.

The following query is returning 0:

select (
    (select COUNT(*) from sax         


        
相关标签:
3条回答
  • 2021-01-28 07:22

    I would do it differently, using two sums:

    select sum
           ( case
             when endOfUse is null and addDate >= '1/1/2014'
             then 1
             else 0
             end
           )
           * 100.0 -- if you want the usual 0..100 range for percentages
           /
           sum
           ( case
             when addDate >= '1/1/2014'
             then 1
             else 0
             end
           )
           percentage
    from   saxref..AuthCycle
    
    0 讨论(0)
  • 2021-01-28 07:29

    It can be done more succinctly by moving the common condition to the where clause:

    select sum(case when endOfUse is null then 1 end) * 100.0 / count(*) percentage
    from saxref..AuthCycle
    where addDate >= '1/1/2014'
    

    Note how you don't need the case of 0 for false either, since nulls are ignored with sum()

    0 讨论(0)
  • 2021-01-28 07:29

    The issue is caused because you are dividing 2 int values, which by default will output an int as it takes the data types used in the calculation to determine the data type of the output, so effectively if you do this:

    select 50/100 as result
    

    You get 0.5 output as 0 as it rounds it to an int (no decimal places).

    If you however specify decimals:

    select 50.0/100.0 as result
    

    You would get 0.5 as a decimal, which you could multiply by 100 to get 50%.

    So updating your syntax to multiply by 1.0 and making the counts into decimals would give you the correct result:

    select (
    (select COUNT(*) from saxref..AuthCycle where endOfUse is null and addDate >= '1/1/2014')*1.0 / 
    (select COUNT(*) from saxref..AuthCycle where addDate >= '1/1/2014')*1.0
    ) as Percentage
    
    0 讨论(0)
提交回复
热议问题