Return multiple values from a function in PHP [closed]

Answer 1

I'm not sure if I gut you right...

list($id,,) = GetCashierDetail(11);

echo $id;

Answer 2

How about:

$arr = GetCashierDetail (11);
extract($arr);
print $cashierId." ".$CashierTotal." ".$CashierLastTotal;

Answer 3

//$UserID - your user's id
$result = GetCashierDetail ($UserID);
//now just using as normal array, for example
echo $result['cashierId'];

Answer 4

If I understood your question correctly, you want to display value of Cashier ID.

You can do it like this..

$cashierData = GetCashierDetail(11);

$ID = $cashierData['cashierId'];

echo 'cashier ID is: ' . $ID;

Similarly you can also get CashierTotal by $cashierData['CashierTotal'] and so on

Answer 5

$return = GetCashierDetail(11);
$id = $return['cashierId'];

RTM: http://php.net/manual/en/language.types.array.php

Answer 6

Why not return just an array?

        function GetCashierDetail ($UserID){
    $GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total 
    FROM `cashiers` 
    WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0' 
    and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'";
    $objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]");
    $GetCashierIDResult = mysql_fetch_array($objQueryCashierID);
    $BillsCashierID = $GetCashierIDResult['cashiers_CashierID'];
    $CashierTotal=$GetCashierIDResult['cashiers_Total']; 
    $CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total']; 
    $num=mysql_affected_rows();
    // Return Data
    return array('cashierId'=>$BillsCashierID ,
                      'CashierTotal'=>$CashierTotal ,
                      'CashierLastTotal'=>$CashierLastTotal );                      

}  

$user = GetCashierDetail($id);
$ID = $user['cashierId'];
echo $ID;