Can there be a database-agnostic SQL query to fetch top N rows?

后端 未结 5 797
有刺的猬
有刺的猬 2021-01-28 05:33

We want to be able to select top N rows using a SQL Query. The target database could be Oracle or MySQL. Is there an elegant approach to this? (Needless to say, we\'re dealing w

相关标签:
5条回答
  • 2021-01-28 06:15

    To get the top 5 scorers from this table:

    CREATE TABLE people
                 (id      int, 
                  name    string, 
                  score   int)
    

    try this SQL:

    SELECT id, 
           name, 
           score
    FROM   people  p
    WHERE  (SELECT COUNT(*) 
            FROM   people p2
            WHERE  p2.score  > p.score 
           ) <=4 
    

    I believe this should work in most places.

    0 讨论(0)
  • 2021-01-28 06:17

    If there is a unique key on the table yes...

    Select * From Table O
    Where (Select Count(*) From Table I
           Where [UniqueKeyValue] < O.UniqueKeyValue)  < N
    

    You can substitute your own criteria if you want the "Top" definition to be based on some other logic than on the unique key...

    EDIT: If the "sort" that defines the meaning of "Top" is based on a non-unique column, or set of columns, then you can still use this, but you can't guarantee you will be able to get exactly N records out...

      Select * From Table O
      Where (Select Count(*) From Table I
             Where nonUniqueCol < O.nonUniqueCol) < 10
    

    If records 8, 9, 10, 11, and 12 all have the same value in [nonUniqueCol], then the query will either only generate 7 records, (with '<') ... , or 12 (if you use '<=')

    NOTE: As this involves a correlated sub-query, the performance can be an issue for very large tables...

    0 讨论(0)
  • 2021-01-28 06:26

    No. The syntax is different.

    You may, however, create views:

    /* Oracle */
    
    CREATE VIEW v_table
    AS
    SELECT  *
    FROM    (
            SELECT  *
            FROM    table
            ORDER BY
                    column
            )
    WHERE   rownum <= n
    
    /* MySQL */
    
    CREATE VIEW v_table
    AS
    SELECT  *
    FROM    table
    ORDER BY
            column
    LIMIT   n
    
    0 讨论(0)
  • 2021-01-28 06:36

    The big problem, after looking this over, is that MySQL isn't ISO SQL:2003 compliant. If it was, you'd have these handy windowing functions:

    SELECT * from
    (   SELECT
        RANK() OVER (ORDER BY <blah>) AS ranking,
        <rest of columns here>,
        FROM <table>
    )
    WHERE ranking <= <N>
    

    Alas, MySQL (and others that mimic it's behavior, eg SQLite), do not, hence the whole limiting issue.

    Check out this snippet from Wikipedia (http://en.wikipedia.org/wiki/Window_function_(SQL)#Limiting_result_rows)

    0 讨论(0)
  • 2021-01-28 06:38

    I don't think that's possible even just between mysql and mssql. I do an option for simulating such behaviour though:

    1. create views that have an auto incremented int column; say 'PagingHelperID'
    2. write queries like: SELECT columns FROM viewname WHERE PagingHelperID BETWEEN startindex AND stopindex

    This will make ordering difficult, you will need different views for every order in which you intend to retreive data.

    You could also "rewrite" your sql on the fly when querying depending on the database and define your own method for the rewriter, but I don't think there is any "good" way to do this.

    0 讨论(0)
提交回复
热议问题