Why can I create multiple instances with the same name in a loop?

Question

I don\'t understand why this works and I hope somebody can explain it to me. Here is an example:

TestObject array[] = new TestObject[10];
for(int i= 0; i <= 1         


        

Answer 1

Every iteration of a loop is a block and, as a block, has its own scope. You can achieve the same result by doing this:

{
    int i = 0;
}
{
    int i = 1;
}
// etc

Answer 2

it's the scope of object problem. every iteration has its scope let's say they are not the same object at all

Answer 3

The scope for a for loop is limited to the iteration. So TestObject object is created and destroyed in each iteration.

Answer 4

This is because 'object' is in visibility scope of current loop iteration, so for next iteration, there can be initialized a new one with the same name (other scope).