Bash - Redirection with wildcards

Question

I\'m testing to do redirection with wildcards. Something like:

./TEST* < ./INPUT* > OUTPUT

Anyone have any recommendations? Thanks.

Answer 1

There is a program called TEST* that has to get various redirection into into called INPUT*, but the thing is there are many TEST programs and they all have a different number, e.g. TEST678. What I'm trying to do is push all the random INPUT files into all the all TEST programs.

You can write:

for program in TEST*            # e.g., program == 'TEST678'
do
  suffix="${program#TEST}"      # e.g., suffix == '678'
  input="INPUT$suffix"          # e.g., input == 'INPUT678'
  "./$program" < "$input"       # e.g., run './TEST678 < INPUT678'
done > OUTPUT

Answer 2

Say you have the following 5 files: TEST1, TEST1, INPUT1, INPUT2, and OUTPUT. The command line

./TEST* < ./INPUT* > OUTPUT

will expand to

./TEST1 ./TEST2 < ./INPUT1 ./INPUT2 > OUTPUT.

In other words, you will run the command ./TEST1 with 2 arguments (./TEST2, ./INPUT2), with its input redirected from ./INPUT1 and its output redirected to OUTPUT.

To address what you are probably trying to do, you can only specify a single file using input redirection. To send input to TEST from both of the INPUT* files, you would need to use something like the following, using process substitution:

./TEST1 < <(cat ./INPUT*) > OUTPUT

---

To run each of the programs that matches TEST* on all the input files that match INPUT*, use the following loop. It collects the output of all the commands and puts them into a single file OUTPUT.

for test in ./TEST*; do
    cat ./INPUT* | $test
done > OUTPUT

Answer 3

for test in ./TEST*; do
 for inp in ./INPUT*; do
   $test < $inp >> OUTPUT
 done
done