Getting all nodes at a level in full binary tree, array format

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囚心锁ツ
囚心锁ツ 2021-01-28 04:52

I need to get all the nodes at a certain level in a full binary tree from either the left or right subtree. I currently retrieve the binary tree from the DB as an array, for exa

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  • 2021-01-28 05:45

    I upvoted BeetleJuice's answer for using the "Shift Left" bitwise operator << -- it is the perfect building block for this task.

    This is as clean as I can make my coding attempt:

    Code: (Demo)

    function getForkinValues($array,$level,$side='left'){ // left side fork is default
        if($level==1) return current($array);
        $length=$level>2?1<<($level-2):1;  // number of elements to return
        $index=(1<<$level-1)-1;            // first index to return
        if($side=='right') $index+=$length;  // shift to correct index for 'right'
        if(!isset($array[$index+$length-1])) return 'Error: Insufficient Array Length';
        return array_slice($array,$index,$length);
    
    }
    $array=['A','B','C','D','E','F','G'];
    var_export(getForkinValues($array,3,'right'));
    
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  • 2021-01-28 05:47
    // Adjust depth as needed
    $depth = 3;
    
    // using bit arithmetic. '<< 3' means multiply by 2 three times.
    $start = 1 << $depth-1; // 1 * (2 * 2) because depth is 3
    $end = (1 << $depth) -1; // 1 * (2 * 2 * 2) - 1
    
    // if depth=3, this is [4,5,6,7]
    $fullLevel = range($start, $end);
    
    print_r($fullLevel);
    
    if($depth > 1):
        $leftBranch = array_slice($fullLevel,0,count($fullLevel)/2);
        $rightBranch = array_slice($fullLevel,count($fullLevel) / 2);
    
        print_r($leftBranch); // [4,5]
        print_r($rightBranch); // [6, 7]
    endif;
    
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