use template to print all the data of any container

Question

I plan to write a function which can print all the data of any container. In other words, I can use with different containers type like vector, deque or list and that I can call

Answer 1

Using c++11 you can simplify it to:

template <typename C>
void print(const C &data){
    for (auto &elem : data)
        cout << elem << " ";
    cout << endl;
}

and call it with print(data). You could also use std::for_each or copy it directly into cout.

Answer 2

As noted in the comments, std::list actually has more than one template parameter (the second parameter is the allocator). Moreover, there is no need for print to take two template parameters; you can simply parameterize it over the overall container type:

#include <iostream>
#include <iterator>
#include <list>
using namespace std;

template <typename C>
void print(const C &data){
    for(auto it=begin(data);it!=end(data);++it){
        cout<<*it<<" ";
    }
    cout<<endl;
}


int main(int argc, char** argv) {
    list<int> data;
    for(int i=0;i<4;i++){
        data.push_back(i);
    }
    print(data);
    return 0;
}

Demo.

As pointed out in the other answer, if you can use C++11 features, a range-for loop is better than the explicit iterator use above. If you can't (which means no auto or std::begin or std::end either), then:

template <typename C>
void print(const C &data){
    for(typename C::const_iterator it=data.begin();it!= data.end();++it){
        cout<<*it<<" ";
    }
    cout<<endl;
}

Note that since we take data by const reference, we need to use const_iterator.