Regex for extracting 3 digits numbers between brackets

Question

My string is:

Frequency/FA ID VerifiedFA0 FAID5(125)/FA1 FAID7(175)/FA2 FAID1(476)

The regex I\'m trying to create should extract these numbers

Answer 1

Slight change:

This finds exactly 3 digits inside of parentheses: ((\d\d\d))

The actual string value (in java) is: "(\\(\\d\\d\\d\\))"

Test on the Java RegEx Test page

Answer 2

Check this out:

String s = "Frequency/FA ID VerifiedFA0 FAID5(125)/FA1 FAID7(175)/FA2 FAID1(476)";
Pattern patt = Pattern.compile("\\(\\d+\\)");
Matcher match = patt.matcher(s);
while(match.find()){
    System.out.println(match.group());
}

Answer 3

Rather than replacing everything that you don't need, you can use Pattern and Matcher class, to extract what you need.

The regex pattern to extract numbers between brackets would be: -

\(\d+\)

+ quantifier is used to match 1 or more repetition of digits. If you want to match just 3 digits, then you can use {3} quantifier with \d: - \(\d{3}\).

You can apply this regex pattern with Matcher#find() method to get all the numbers from that string. I leave the task of implementation to you.