How can I check in Python 3 that a string contains only characters/symbols from a given list?
Given:
allowedSymbols = [\'b\', \'c\', \'z\', \'
I am not a python expert, but something below will work
for c in enteredpass:
if c not in allowedSymbols:
return 0
The more Pythonic way is to use all(), it's faster, shorter, clearer and you don't need a loop:
allowedSymbols = ['b', 'c', 'z', ':']
enteredpass1 = 'b:c::z:bc:'
enteredpass2 = 'bc:y:z'
# We can use a list-comprehension... then apply all() to it...
>>> [c in allowedSymbols for c in enteredpass1]
[True, True, True, True, True, True, True, True, True, True]
>>> all(c in allowedSymbols for c in enteredpass1)
True
>>> all(c in allowedSymbols for c in enteredpass2)
False
Also note there's no gain in allowedSymbols
being a list of chars instead of a simple string: allowedSymbols = 'bcz:'
(The latter is more compact in memory and probably tests faster too)
But you can easily convert the list to a string with ''.join(allowedSymbols)
>>> allowedSymbols_string = 'bcz:'
>>> all(c in allowedSymbols_string for c in enteredpass1)
True
>>> all(c in allowedSymbols_string for c in enteredpass2)
False
Please see the doc for the helpful builtins any() and all(), together with list comprehensions or generator expressions they are very powerful.
Use sets for membership testing: keep the symbols in a set then check if it is a superset of the string.
>>> allowed = {'b', 'c', 'z', ':'}
>>> pass1 = 'b:c::z:bc:'
>>> allowed.issuperset(pass1)
True
>>> pass2 = 'f:c::z:bc:'
>>> allowed.issuperset(pass2)
False
>>> allowed.issuperset('bcz:')
True
This should do it.
for i in enteredpass:
if i not in allowedSymbols:
print("{} character is not allowed".format(i))
break
Not sure what you're looking for with the Score = score -5. If you want to decrease score by 5 if all entered characters are in the allowedSymbols list just put score = score - 5 on the same indentation level as the for loop, but at the end of the code after the if block.