MySQLi failing to prepare a statement

Question

I\'m running two queries in my script room.php. Both are using MySQLi prepared statements, and their code are as follows:

/* Get room name */
$stmt          


        

Answer 1

All of the mysqli functions/methods can fail in which case they will return false. I.e. if prepare() fails $stmt isn't an object you can call a method on but a bool(false). You have to check the return values and add some error handling, e.g.

$stmt = $mysqli->prepare('SELECT name FROM `rooms` WHERE r_id=?');
if ( !$stmt ) {
    printf('errno: %d, error: %s', $mysqli->errno, $mysqli->error);
    die;
}

$b = $stmt->bind_param('i', $roomID);
if ( !$b ) {
    printf('errno: %d, error: %s', $stmt->errno, $stmt->error);
}

$b = $stmt->execute();
if ( !$b ) {
  and so on and on

see http://docs.php.net/mysqli-stmt.errno et al

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in this case you probably bumped into the problem that you can't create an other statement while there are still results/result sets pending for the previous statement.
see http://docs.php.net/mysqli-stmt.close:

Closes a prepared statement. mysqli_stmt_close() also deallocates the statement handle. If the current statement has pending or unread results, this function cancels them so that the next query can be executed.