How to know if a list has an even or odd number of elements

Question

How can I find out if there is even, or odd, number of elements in an arbitrary list.

I tried list.index() to get all of the indices... but I still don\'t k

Answer 1

if len(mylist)%2==0:
     #even
else:
     #odd

Answer 2

Using the modulus operator - % gives the remainder. To get if even, you need to divide by 2, for example:

7 % 2 = 1
8 % 2 = 0

The most pythonic way to do it is:

def is_even(your_list):
    if not len(your_list) % 2:  # 0 in case of even i.e. No remainder
        return True
    else:
        return False