1
A1
1000
<
If you have the option of using for-each-group, I'd definitely use that over Muenchian grouping...
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<Output>
<xsl:for-each-group select="Entry" group-by="substring(Details/Code,1,1)">
<Code-group>
<xsl:value-of select="current-grouping-key()"/>
</Code-group>
<Sum>
<xsl:value-of select="sum(current-group()/Details/Value)"/>
</Sum>
</xsl:for-each-group>
</Output>
</xsl:template>
</xsl:stylesheet>
Fiddle: http://xsltfiddle.liberty-development.net/jxNakzX
If you truly want to hard code the "A" -> A1, A2 and "B" -> B1, B2 mapping, you could use xsl:key and not group at all...
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="A" match="Entry[Details/Code=('A1','A2')]" use="'A'"/>
<xsl:key name="B" match="Entry[Details/Code=('B1','B2')]" use="'B'"/>
<xsl:template match="/*">
<xsl:variable name="ctx" select="."/>
<Output>
<xsl:for-each select="('A','B')">
<xsl:variable name="key" select="."/>
<Code-group>
<xsl:value-of select="$key"/>
</Code-group>
<Sum>
<xsl:value-of select="sum($ctx/key($key,$key)/Details/Value)"/>
</Sum>
</xsl:for-each>
</Output>
</xsl:template>
</xsl:stylesheet>
Fiddle: http://xsltfiddle.liberty-development.net/jxNakzX/1
The hardcoding requirement is difficult to understand. Perhaps you want to do something like:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:key name="entry" match="Entry" use="Details/Code"/>
<xsl:template match="/root">
<Output>
<Code-group> A </Code-group>
<Sum>
<xsl:value-of select="sum(key('entry', ('A1', 'A2'))/Details/Value)" />
</Sum>
<Code-group> B </Code-group>
<Sum>
<xsl:value-of select="sum(key('entry', ('B1', 'B2'))/Details/Value)" />
</Sum>
</Output>
</xsl:template>
</xsl:stylesheet>