Transform a natural number to a specific base and return it as a list

Question

I want to show the result of my function as a list not as a number. My result is:

(define lst (list ))
(define (num->base n b)
  (if (zero? n)
     (append ls         


        

Answer 1

I think you have to rethink this problem. Appending results to a global variable is definitely not the way to go, let's try a different approach via tail recursion:

(define (num->base n b)
  (let loop ((n n) (acc '()))
    (if (< n b)
        (cons n acc)
        (loop (quotient n b)
              (cons (modulo n b) acc)))))

It works as expected:

(num->base 12345 10)
=> '(1 2 3 4 5)