I want to pass an overloaded operator to a function, which can\'t figure out which of the two overloads it should use.
// This works, not overloaded:
chai.add(ch
The following may help you to choose one overload of map::operator[]
static_cast<
std::string& (std::map<std::string, std::string>::*)(const std::string&)>(
&std::map<std::string, std::string>::operator []);
Or with a typedef
:
using MyMap = std::map<std::string, std::string>;
static_cast<std::string& (MyMap::*)(const std::string&)>(&MyMap::operator []);
// ReturnType Class params
Firstly, operators are just functions with a special syntax. So, overloaded operators are just overloaded functions. With that in mind, you question boils down to "How do I select one of an overloaded set of functions?". The simple answer to that is the use of a static_cast.
Alternatively, I think you can also use it in a context where the context already dictates which of the overloads to select. In your case, you are using a template function (I think) and it doesn't work there because it needs the type to instantiate the template and it needs the template instatiation to select the type and thus the overload. Using a temporary variable is one way to resolve this, another is to explicitly specify the template function (like e.g. max<float>(0, x)
where otherwise 0 is considered of integer type).