Bash text file editing/modifying

Question

I have a text file that I am trying to modify. I am taking the input file that has lines of the form of

(y+1/4,-x+1/2,z+3/4)

and trying to chan

Answer 1

#!/usr/bin/env bash

filename="227.dat"

re='[(]y[+]([[:digit:]/]+),-x[+]([[:digit:]/]+),z[+]([[:digit:]/]+)[)]';
while IFS= read -r line; do
    if [[ $line =~ $re ]]; then
        printf '\t%s' \
            0 1 0 \
           -1 0 0 \
            0 0 1 \
            "${BASH_REMATCH[1]}" \
            "${BASH_REMATCH[2]}" \
            "${BASH_REMATCH[3]}";
        printf '\n';
    else
        echo "ERROR: $line does not match $re" 1>&2;
    fi;
done <"$filename"

...given, your input, returns:

   0       1       0       -1      0       0       0       0       1       1/4     1/2     3/4

...which as far as I can tell is correct.

---

A more complex approach, making unfounded extrapolations (given the lack of detail and exemplars in the question itself), might look like:

#!/usr/bin/env bash
while IFS='(),' read -a pieces; do
  declare -A vars=( [x]=1 [y]=1 [z]=1 [x_sigil]='' [y_sigil]='' [z_sigil]='' )
  for piece in "${pieces[@]}"; do
    #                1   2      3   4
    if [[ $piece =~ (-?)([xyz])([+]([[:digit:]/]+))? ]]; then
      if [[ ${BASH_REMATCH[4]} ]]; then                 # only if there *are* digits
        vars[${BASH_REMATCH[2]}]=${BASH_REMATCH[4]}     # ...then store them.
      fi
      vars[${BASH_REMATCH[2]}_sigil]=${BASH_REMATCH[1]} # store - if applicable
    fi
  done
  printf '\t%s' \
    "0"                 "${vars[x_sigil]}1" 0 \
    "${vars[y_sigil]}1" 0                   0 \
    0                   0                   "${vars[z_sigil]}1" \
    "${vars[y]}"        "${vars[x]}"        "${vars[z]}"
  printf '\n'
done

Given the sample inputs provided in a comment on this answer, output is:

0   1   0   1   0   0   0   0   1   1   1   1
0   1   0   1   0   0   0   0   1   1   1   1
0   1   0   1   0   0   0   0   1   1   1   1
0   1   0   1   0   0   0   0   -1  3/4 1/4 1/2
0   1   0   -1  0   0   0   0   1   1/2 3/4 1/4
0   -1  0   1   0   0   0   0   1   1/4 1/2 3/4
0   -1  0   -1  0   0   0   0   -1  1   1   1
0   -1  0   -1  0   0   0   0   -1  1   1   1
0   -1  0   -1  0   0   0   0   -1  1   1   1
0   -1  0   -1  0   0   0   0   1   1/4 3/4 1/2
0   -1  0   1   0   0   0   0   -1  1/2 1/4 3/4
0   1   0   -1  0   0   0   0   -1  3/4 1/2 1/4
0   -1  0   -1  0   0   0   0   1   1/4 3/4 1/2
0   -1  0   -1  0   0   0   0   1   1/4 3/4 1/2
0   -1  0   -1  0   0   0   0   1   1/4 3/4 1/2
0   -1  0   -1  0   0   0   0   -1  1   1   1
0   -1  0   1   0   0   0   0   1   1/4 1/2 3/4
0   1   0   -1  0   0   0   0   1   1/2 3/4 1/4
0   1   0   1   0   0   0   0   -1  3/4 1/4 1/2
0   1   0   1   0   0   0   0   -1  3/4 1/4 1/2
0   1   0   1   0   0   0   0   -1  3/4 1/4 1/2
0   1   0   1   0   0   0   0   1   1   1   1
0   1   0   -1  0   0   0   0   -1  3/4 1/2 1/4
0   -1  0   1   0   0   0   0   -1  1/2 1/4 3/4
0   -1  0   1   0   0   0   0   -1  1/2 1/4 3/4
0   -1  0   1   0   0   0   0   -1  1/2 1/4 3/4
0   -1  0   1   0   0   0   0   -1  1/2 1/4 3/4
0   -1  0   1   0   0   0   0   1   1/4 1/2 3/4

Answer 2

Here's an approach that may simplify the parsing. Read each line into an array using IFS set to all possible delimiters and characters you don't care about:

while IFS=$'\(\)+,' read -ra line; do
    for i in 1 3 5; do
        case "${line[$i]}" in
            x) printf "%s\t%s\t%s\t" 1 0 0 ;;
            y) printf "%s\t%s\t%s\t" 0 1 0 ;;
            z) printf "%s\t%s\t%s\t" 0 0 1 ;;
            -x) printf "%s\t%s\t%s\t" -1 0 0 ;;
            -y) printf "%s\t%s\t%s\t" 0 -1 0 ;;
            -z) printf "%s\t%s\t%s\t" 0 0 -1 ;;
        esac
    done
    for i in 2 4 6; do
        printf "%s\t" "${line[$i]}"
    done
    echo
done < "$filename"