XML-XSLT : How to compare two dates which are in String

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清歌不尽
清歌不尽 2021-01-27 19:02

I know this question might get repeated and also I have went through similar articles and question but I have not found the exact solution.

Now the question I am using <

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  • 2021-01-27 19:16

    XSLT (2.0) recognizes dates in YYYY-MM-DD format only, and date-times in YYYY-MM-DDThh:mm:ss format only. In order to compare the strings as dates, (or, in this case, date-times), you must first convert them to valid date-times. Since you need to do this more than once, it would be convenient to construct a function for this purpose:

    XSLT 2.0

    <xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:my="http://www.example.com/my"
    exclude-result-prefixes="xs my">
    <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
    <xsl:strip-space elements="*"/>
    
    <xsl:variable name="oldDate" select="'29.05.2015 15:25:06'" />
    <xsl:variable name="currentDate" select="'27.07.2015 14:28:02'" />
    
    <xsl:function name="my:string-to-datetime">
        <xsl:param name="string"/> 
        <xsl:variable name="parts" select="tokenize($string,'\.|\s')"/>
        <xsl:sequence select="xs:dateTime(concat($parts[3], '-', $parts[2], '-', $parts[1], 'T', $parts[4]))" />
    </xsl:function>
    
    <xsl:template match="/">
        <result>
            <xsl:value-of select="if (my:string-to-datetime($oldDate) gt my:string-to-datetime($currentDate)) then 'OK' else 'Not Ok'" />
        </result>
    </xsl:template>
    
    </xsl:stylesheet>
    

    Result

    <?xml version="1.0" encoding="utf-8"?>
    <result>OK</result>
    

    Note that this assumes your strings come in a DD.MM.YYYY hh:mm:ss format - i.e. that the days are padded to two digits - otherwise there's more work to be done.

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  • 2021-01-27 19:22

    Given this input XML:

    <?xml version="1.0" encoding="UTF-8"?>
    <root>
        <oldDate>29.05.2015 15:25:06</oldDate>
        <currentDate>27.07.2015 14:28:02</currentDate>
    </root>
    

    and this stylesheet:

    <?xml version="1.0" encoding="UTF-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        version="2.0">
    
        <xsl:output omit-xml-declaration="yes"/>
    
        <xsl:variable name="raw_oldDate" select="substring-before(root/oldDate, ' ')"/>
        <xsl:variable name="raw_currentDate" select="substring-before(root/currentDate, ' ')"/>
    
    
        <xsl:template match="/">
            <xsl:choose>
                <xsl:when test="number(concat(substring($raw_oldDate, 7, 4), 
                    substring($raw_oldDate, 4, 2),
                    substring($raw_oldDate, 1, 2),
                    translate(substring-after(root/oldDate, ' '), ':', '')))
                    &lt;
                    number(concat(substring($raw_currentDate, 7, 4), 
                    substring($raw_currentDate, 4, 2),
                    substring($raw_currentDate, 1, 2),
                    translate(substring-after(root/currentDate, ' '), ':', '')))">
                    <xsl:text>OK</xsl:text>
                </xsl:when>
                <xsl:otherwise>
                    <xsl:text>not OK</xsl:text>
                </xsl:otherwise>
            </xsl:choose>
        </xsl:template>
    
    </xsl:stylesheet>
    

    it produces:

    OK
    
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