How to disemvowel a string with a condition where if the letter “g” is right beside a vowel, it would also be considered a vowel?

Question

Working on a homework question where all the vowels in a string need to be removed and if the letter \"g\" is beside a vowel, it would also be considered a vowel. For example gi

Answer 1

Interesting, does this stack?

So if you had the word baggga, would the outer g's turn into vowels, which then would turn the inner g also into a vowel? So is the output bg or is it b?

You can either remove all g's next to vowels and then in a second step remove all vowels.

Or you could replace all g's next to vowels by, let's say 'a', and then remove all vowels. If the 'g is a vowel'-rule stacks, you may have to repeat the first step until the string does not change anymore.

Answer 2

You can try using regex:

import re

def disemvowel(text):
    return re.sub(r"G?[AEIOU]+G?", "", text, flags=re.IGNORECASE)


tests = {"fragrance": "frrnc", "gargden": "rgdn", "gargdenag": "rgdn", "gag": ""}

for test, value in tests.items():
    assert disemvowel(test) == value

print("PASSED")

Output:

PASSED

Answer 3

You can add a variable to track if the previous letter was a vowel.

def disemvowel(text):
text = list(text)
new_letters = []
last_vowel_state=False
for i in text:
    if i.lower() == "a" or i.lower() == "e" or i.lower() == "i" or i.lower() == "o" or i.lower() == "u":
        last_vowel_state=True
        pass
    else:
        if last_vowel_state==True and i.lower()=='g':
            pass
        else:    
            new_letters.append(i)
        last_vowel_state=False


print (''.join(new_letters))

Input

disemvowel('fragrance')

Output

frrnc

Input

disemvowel('gargden')

Output

grgdn