date validation not to be today

Question

I need to validate 2 date that never should be same.If same it will return false.Code is in PHP.It is always giving o/p as false.

function BeforeAdd($values, $me         


        

Answer 1

U can use fucntion strtotime and compare it

 $d1 = "1/2/2015";
 $d2= "1/2/2016";

    if ( strtotime($d1) == strtotime($d2) )
       echo "same";
     else
       echo "different";

copy this code and test it i resolve your problem this is my last edit

<?php
$d1 = "1/2/2015";
$d2= "1/2/2015";





    if ( strtotime($d1) != strtotime($d2) ) {
        return true;  
    }
    else
    {

    echo '<script type="text/javascript">';
    echo 'alert("Application date and leave date should be different.")';
    echo '</script>';

    return false;
    }

?>

Answer 2

function BeforeAdd($values, $message='', $inline='', $pageObject='') {

    $d1 =$values['DATE'];     //date 1 in dd/mm/yyyy format
    $d2 =$values['DATE_OF_LEAVE'];   //date 2 in dd/mm/yyyy format

    if($d1 <> $d2) {
        return true;  
    }

    echo '<script type="text/javascript">';
    echo 'alert("Application date and leave date should be different.")';
    echo '</script>';

    return false; 


}

You need to change $values['DATE OF LEAVE'] to $values['DATE_OF_LEAVE']. Also in the example you have some fields you don't use - I made them optional and changed the javascript code a little.

Answer 3

Any one can suggest me a code to return false id date is today else true in the format

function BeforeAdd($values, $message, $inline, $pageObject)
{
    $d1 = $values['DATE'];     //date 1 in dd/mm/yyyy format
    $d2 = now();  

    if($d1>$d2)
    {
        return true;  
    }

    echo '<script language="javascript">';
    echo 'alert(Application date and leave date should be different.)';
    echo '</script>';

    return false;  
}