How to print text between specific words(as Inputs arguments) in Shell scripting

Question

I want to print complete text between specific words. Here is my requirement.

\"123.log\" contain below text.

EBSPRODSTART
web logic server
Oracle databa         


        

Answer 1

There are three problems with your code:

1. '...' doesn't interpolate any variables. You need "..." for that.
2. $DBNAMESTART looks for a variable called DBNAMESTART. You need ${DBNAME}START.
3. DBANEMEND is not the same as DBNAMEEND.

Thus:

sed -n "/^${DBNAME}START\$/,/^${DBNAME}END\$/p"