Table 1: Tracks
Table 2: Wordlist
Table 3: N:M Track has Words (trackwords)
Find all tracks which have all the words.
currently the query looks l
Would probably be faster if you broke this up into two queries. First, a join of the words and trackwords to net you all the trackids you need. Then go back to the track table and do:
WHERE t.id IN(...trackids here...)
but based on the query above all you're returning is t.id which you have from tw.trackid already.
Your problem set is very much like that of storing tags for an item like StackOverflow or Del.icio.us does.
The article Tags: Database schemas proposes several solutions, among them @ChssPly76's idea.
There's no point in left joins if you're only looking for tracks that have all the words. I'm assuming that (trackid
,wordid
) combination is unique in trackwords
.
SELECT t.id
FROM track as t, trackwords as tw, wordlist as wl
WHERE t.id=tw.trackid
AND wl.id=tw.wordid
AND wl.trackusecount>0 /* not sure what that is - you have it in your query */
AND wl.word in ('folsom','prison','blues')
GROUP by t.id
HAVING count(*) = 3
This query would benefit from indexes on wordlist(word), trackwords(trackid,wordid) and track(id).