I have the code below, I just need help on figuring out the best way to get html from the content node below instead of plaintext. Any help is much appreciated.
In my experience the best way of handling XML with Classic ASP is to use an XSL stylesheet.
XSLT is quite easy to learn at a basic level, although the learning curve gets a bit steeper later on.
I recommend the w3schools tutorial
http://www.w3schools.com/xsl/
Once you've written your stylesheet, if you have a local XML source your asp code would look like this
set xml = Server.CreateObject("Msxml2.DomDocument")
xml.load(Server.Mappath("source.xml"))
set xsl = Server.CreateObject("Msxml2.DomDocument")
xsl.load(Server.Mappath("stylesheet.xsl"))
Response.Write(xml.transformNode(xsl))
set xsl = nothing
set xml = nothing
If the xml is from a remote url then it's a little more complex
set xml = Server.CreateObject("Msxml2.DomDocument")
xml.setProperty "ServerHTTPRequest", true
xml.async = false
xml.validateOnParse = false
xml.load("http://xmlsource.com")
set xsl = Server.CreateObject("Msxml2.DomDocument")
xsl.load(Server.Mappath("stylesheet.xsl"))
Response.Write(xml.transformNode(xsl))
set xsl = nothing
set xml = nothing
Edit
<h2><%= Title %></h2>
You can get the XML of a node using the xml
property instead of the text
property you are using now:
dim o_xml, o_node
set o_xml = Server.CreateObject("Msxml2.DomDocument")
o_xml.load("books.xml")
set o_node = o_xml.selectSingleNode("//catalog/book[@id='bk102']")
Response.Write Server.htmlEncode(o_node.xml)
Docs here: http://msdn.microsoft.com/en-us/library/ms755989%28v=vs.85%29.aspx