Data Type Truncation

Question

I have a basic C question.

Suppose I\'ve declared and initialized a standard 16 bit unsigned integer

uint16_t var1 = 0x1234;

and then s

Answer 1

Yes. The compiler would internally interpret this as

var2 = (uint8_t)var1;

which would result in var2 having the value 0x34.

Answer 2

I think you mean:

uint16_t var1 = 0x1234;
uint8_t var2;
var2 = var1;

Yes, this will truncate var1 to fit within var1's data type, so var2 will be equal to 0x34.