I am trying to launch a .bat file but I get the error
System cannot find the file C:\\ProgramData\\Oracle\\Java\\javapath\\java.exe
I understand that this is pro
First of all, the path that you provided i.e. C:\ProgramData\Oracle\Java\javapath\java.exe
doesn't appear to be correct. It should point to either JRE or JDK folder that you (probably) have in here:
C:\Program Files (x86)\Java\jdk1.8.0_25\bin
In there you should at least see the following files (and hence, the addition of this bin directory to your PATH variable in the env vars):
java.exe
javac.exe
javaw.exe
javap.exe
java.h.exe
java-rmi.exe
javadoc.exe
jarsigner.exe
jar.exe
If you don't see the files above, something is definitely wrong! Also, even if you were using JRE (not JDK), you should still have this bin folder present, where java.exe resides.
I had the same problem. Here's what worked for me:
Go into your path variable and delete: C:\ProgramData\Oracle\Java\javapath\
.
Then add a new one called: %JAVA_HOME\bin
This post helped: java-path-is-not-pointing-to-sdk-path-in-windows
Edit: Sorry, I just noticed that this question was 3 years old.
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@ECHO OFF
:: Export java settings from registry to a temporary file
START /W REGEDIT /E %Temp%\java.reg "HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft"
if not exist "%Temp%\java.reg" (
START /W REGEDIT /E %Temp%\java.reg "HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\JavaSoft"
)
if not exist "%Temp%\java.reg" (
echo java not installed
exit /b 1
)
:: Find java location
FOR /F "tokens=1* delims==" %%A IN ('TYPE %Temp%\java.reg ^| FIND "INSTALLDIR"') DO SET "JAVA_HOME=%%B"
SET "JAVA_HOME=%JAVA_HOME:"=%"
SET "JAVA_HOME=%JAVA_HOME:\\=\%"
::SET JAVA_HOME
set "java=%java_home%\bin\java.exe"
"%java%" -version
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Try this to see if you can automatically can detect the java location.And if it's work you can put this at the beginning of your script and use %java%
in your script (though it will decrease the performance).