how do you convert a factor that has 3 digits miliseconds to datetime in R?

Question

I time a t object like this:

t<-c(\"2016-10-19 00:00:00.000\")

I need to convert to POSIXct as this:

as.POSIXct(t, format=\"         


        

Answer 1

You could use lubridate too :

library(lubridate)
t<-c("2016-10-19 00:00:00.000")
ymd_hms(t)
#> [1] "2016-10-19 UTC"

Answer 2

The new and easy-to-use package anytime is an alternative:

library(anytime) 
anydate(t$Datetime)

Answer 3

You didn't lose them, that's just the default for when the hours, minutes and seconds are zero. You can specify a format string to force these to be printed:

> ct <- as.POSIXct(t, format="%Y-%m-%d %H:%M:%OS")
> format(ct, "%Y-%m-%d %H:%M:%S")
[1] "2016-10-19 00:00:00"