I have a problem...In the following example i don\'t want that the div who is fixed get over the div with the background red.
Here is the example:
http://jsfiddl
Just give the z-index.
Hope it helps...
http://jsfiddle.net/HFjU6/1/#run
#fixedContainer {
background-color:#ffffd;
position: fixed;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
margin-left: -100px; /*half the width*/
z-index: 2;
}
.div-red {
position: relative;
z-index: 5;
}
<div id="fixedContainer"></div>
<div style="height:200px;background-color:#bbb;"></div>
<div style="height:500px;background-color:red;" class="div-red"></div>
Alright, I think I get what the OP wants. He wanted a container that stays fixed on the top of the viewport, but remains confined by a parent. This behaviour is known as a conditional sticky behaviour, and is actually implemented in both Firefox (without vendor prefix) and macOS/iOS Safari (with -webkit-
prefix): see position: sticky.
Therefore the easiest (but also the least cross-browser compatible) way is simply to modify your markup, such that the sticky element stays within a parent, and you declare position: sticky
on it:
* {
margin: 0;
padding: 0;
}
#fixedContainer {
background-color: #ffffd;
position: -webkit-sticky;
position: sticky;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
transform: translate(-50%, 0); /* Negative left margins do not work with sticky */
}
#div1 {
height: 200px;
background-color: #bbb;
}
#div1 .content {
position: relative;
top: -100px; /* Top offset must be manually calculated */
}
#div2 {
height: 500px;
background-color: red;
}
<div id="div1">
<div id="fixedContainer">I am a sticky container that stays within the sticky parent</div>
<div class="content">Sticky parent</div></div>
<div id="div2">Just another element</div>
An alternative would be to use a JS-based solution. In this case, you do not actually have to modify your markup. I have changed the IDs for easier identification of the elements, however.
The gist of the logic is this:
top
position of the sticky content so that it remains visually in the parent.$(function() {
$(window).scroll(function() {
var $c = $('#sticky-container'),
$s = $('#sticky-content'),
$t = $(this); // Short reference to window object
if ($t.scrollTop() > $c.outerHeight() - $s.outerHeight()) {
$s.css('top', $c.offset().top + $c.outerHeight() - $t.scrollTop() - $s.outerHeight());
} else {
$s.css('top', 0);
}
});
});
* {
margin: 0;
padding: 0;
}
div {
height: 500px;
background-color: red;
}
#sticky-container {
background-color: #bbb;
height: 200px;
}
#sticky-content {
background-color: #ffffd;
position: fixed;
width: 200px;
height: 100px;
margin-left: -100px;
left: 50%;
top: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="sticky-content">Sticky content that stays within the bounds of #div1</div>
<div id="sticky-container">Sticky confinement area</div>
<div>Other content</div>
Old answer before OP clarified the question appropriately:
Just give them the appropriate z-index
values. In this case, you want to:
position: relative
for the large elements, in conjunction with the originally position: fixed
element.<div>
element to have the lowest z-index
, followed by the position fixed element, and then by the red element.There are some catchalls to stacking though: the stacking context is reset when you traverse up or down the node tree. For example, the example will not work if the elements are not siblings.
Here is a proof-of-concept example, modified from your fiddle so that inline CSS is removed.
* {
margin: 0;
padding: 0;
}
#fixedContainer {
background-color: #ffffd;
position: fixed;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
margin-left: -100px;
z-index: 2;
}
#div1 {
height: 200px;
background-color: #bbb;
position: relative;
z-index: 1;
}
#div2 {
height: 500px;
background-color: red;
position: relative;
z-index: 3;
}
<div id="fixedContainer">z-index: 2</div>
<div id="div1">z-index: 1</div>
<div id="div2">z-index: 3</div>