Cut string after specified character in php

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I try to cut a text after the occurence of a specified character, in this case:

“

The text example is:

...text?“ Text,

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2条回答

無奈伤痛

2021-01-27 06:54

The strpos() command requires 3 parameters

1) The Variable

2) The start column and

3) the numbers of characters

If you just use substr($title,$pos2) you get the text from the pos2 column to the end of the string.

<?php
$title = 'before“after';
$pos2 = strpos($title, '“');
if ($pos2 !== false) {
    $header_title = substr($title,0, $pos2+1);
} else {
    // you might want to set $header_title to something in here
    $header_title = 'ELSE';
}
echo $header_title;

RESULT

before“

Also test for not equal false as strpos returns FALSE if it does not find the character you are searching for

After all the discussion below I ran it on my local Apache/PHP

<?php
$title = 'before“after';
$pos2 = strpos($title, '“');
if ($pos2 !== false) {
    $header_title = substr($title,0,$pos2+1);
} else {
    // you might want to set $header_title to something in here
    $header_title = 'ELSE';
}
?>
<!DOCTYPE html>
<html>
<head>
    <title><?php echo $header_title;?></title>
</head>
<body>

    <div> Ello Wurld</div>

</body>
</html>

Produces:

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盖世英雄少女心

2021-01-27 07:09

I think this can be helpful for anyone :

$title = 'sometext?"othertext';
$pos2 = strpos($title, '"');

$title = substr($title, 0, $pos2+1);

echo $title;

Output:

sometext?"

If you want the text after the " mark:

$title = 'sometext?"othertext';
$pos2 = strpos($title, '"');

$title = substr($title, $pos2+1);

echo $title;

Output:

othertext

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