Promise override causes then calls to error

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北海茫月
北海茫月 2021-01-27 05:03

I have the following sample code.

class test extends Promise {
    constructor(executor) {
        super(executor)
    }

    static getPromise() {
        retur         


        
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  • 2021-01-27 06:00

    Why are these not equivalent, and why is this erroring?

    Your overridden constructor does never call the executor and pass it the promise resolving functions (resolve and reject). They are important! You cannot subclass Promise and change the interface like that.

    Why does this throw an error when you call new test() that doesn't use the constructor? It does not. It throws the error when you call t.then(…), which tries to construct a new promise (for its return value) and uses t's constructor for that. It does pass a proper executor callback, and expects it to be called synchronously with resolve and reject - which your code does not do. After the call, it bitches about not having got two functions.

    How can I make this work as I expect?

    Don't use promise subclassing. There's no reason for it. You just want to have a normal function that returns a promise. Use

    const test = {
        getPromise() {
            return Promise.resolve(true)
        }
    };
    test.getPromise().then(…);
    

    or

    function test() {
        return Promise.resolve(true);
    }
    test().then(…);
    
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