I\'m fairly new to XSLT and I am stuck with a problem where I have an Element with an unknown amount of children, and I need to display these children in a table such that there
One approach is to use two recursive templates:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ext="http://exslt.org/common"
xmlns:fo="http://www.w3.org/1999/XSL/Format"
exclude-result-prefixes="ext">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<!-- set the number of columns you want globally -->
<xsl:param name="set-cols" select="'5'"/>
<xsl:template match="books">
<!-- count the needed rows -->
<xsl:variable name="set-row" select="ceiling(count(book) div $set-cols)"/>
<fo:table margin-left="auto" margin-right="auto">
<fo:table-body>
<xsl:call-template name="rows">
<xsl:with-param name="books">
<xsl:apply-templates/>
</xsl:with-param>
<xsl:with-param name="set-row" select="$set-row"/>
</xsl:call-template>
</fo:table-body>
</fo:table>
</xsl:template>
<!-- rows -->
<xsl:template name="rows">
<xsl:param name="books" select="''"/>
<xsl:param name="set-row" select="''"/>
<xsl:param name="count-rows" select="'0'"/>
<xsl:if test="$set-row > 0">
<fo:table-row table-layout="fixed">
<xsl:call-template name="cols">
<xsl:with-param name="books" select="$books"/>
<xsl:with-param name="count-rows" select="$count-rows"/>
</xsl:call-template>
</fo:table-row>
<xsl:call-template name="rows">
<xsl:with-param name="books" select="$books"/>
<xsl:with-param name="set-row" select="$set-row - 1"/>
<xsl:with-param name="count-rows" select="$count-rows + 1"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
<!-- columns -->
<xsl:template name="cols">
<xsl:param name="books" select="''"/>
<xsl:param name="cols" select="$set-cols"/>
<xsl:param name="count-rows" select="''"/>
<xsl:param name="count-cols" select="'1'"/>
<xsl:if test="$cols > 0">
<fo:table-cell border="1">
<fo:block font-weight="bold">
<xsl:variable name="book" select="ext:node-set($books)//book[position() = ($count-rows * $set-cols + $count-cols)]"/>
<xsl:value-of select="$book/author"/>
</fo:block>
</fo:table-cell>
<xsl:call-template name="cols">
<xsl:with-param name="books" select="$books"/>
<xsl:with-param name="cols" select="$cols - 1"/>
<xsl:with-param name="count-rows" select="$count-rows"/>
<xsl:with-param name="count-cols" select="$count-cols + 1"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
With yout input
<books>
<book>
<author>Ralls, Kim</author>
<title>Midnight Rain</title>
</book>
<book>
<author>Corets, Eva</author>
<title>Maeve Ascendant</title>
</book>
<!-- ... -->
</books>
you get:
<fo:table margin-left="auto" margin-right="auto" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<fo:table-body>
<fo:table-row table-layout="fixed">
<fo:table-cell border="1">
<fo:block font-weight="bold">Ralls, Kim</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Corets, Eva</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Corets, Eva</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Randall, Cynthia</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Thurman, Paula</fo:block>
</fo:table-cell>
</fo:table-row>
<fo:table-row table-layout="fixed">
<fo:table-cell border="1">
<fo:block font-weight="bold">Knorr, Stefan</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Kress, Peter</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Crichton, Michael</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Orwell, George</fo:block>
</fo:table-cell>
<fo:table-cell border="1">
<fo:block font-weight="bold">Martin, George</fo:block>
</fo:table-cell>
</fo:table-row>
</fo:table-body>
</fo:table>
The previous answers are way to complicated for what should be (and is) easy. Recursion is not required for such a simple thing.
In XSL FO you do not need to structure tables with rows. You can use the attribute "ends-row" to specify that you are ending a row and starting a new one. You can easily adapt this simple example and even pass in the "number of columns" (see the mod 5 ... which means after every fifth one start a new row ... change to 4 or 8 or whatever you wish) ... You would just create the structure for the table (fo:table and fo:table-body) outside of this. Inside the table body just put cells as children like this template does:
<xsl:template match="book">
<xsl:variable name="pos" select="position()"/>
<fo:table-cell>
<xsl:if test="not($pos mod 5)">
<xsl:attribute name="ends-row">true</xsl:attribute>
</xsl:if>
<fo:block>
<xsl:value-of select="author"/>
</fo:block>
</fo:table-cell>
</xsl:template>
So putting this into a simple example with your data ... see below. Formats your XML into five columns per row.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
version="1.0">
<xsl:template match="/">
<fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format">
<fo:layout-master-set>
<fo:simple-page-master margin-top="1in" margin-left="1in" margin-bottom="1in"
margin-right="1in" page-width="8in" page-height="11in" master-name="first">
<fo:region-body margin-top="0pt"/>
<fo:region-before extent="0pt"/>
<fo:region-after extent="0pt"/>
</fo:simple-page-master>
</fo:layout-master-set>
<fo:page-sequence master-reference="first">
<fo:flow flow-name="xsl-region-body" font-size="12pt" font-family="Helvetica">
<xsl:apply-templates/>
</fo:flow>
</fo:page-sequence>
</fo:root>
</xsl:template>
<xsl:template match="books">
<fo:table>
<fo:table-body>
<xsl:apply-templates/>
</fo:table-body>
</fo:table>
</xsl:template>
<xsl:template match="book">
<xsl:variable name="pos" select="position()"/>
<fo:table-cell border="1pt solid black">
<xsl:if test="not($pos mod 5)">
<xsl:attribute name="ends-row">true</xsl:attribute>
</xsl:if>
<fo:block>
<xsl:value-of select="author"/>
</fo:block>
</fo:table-cell>
</xsl:template>
</xsl:stylesheet>