program ignoring if statement, and printing True when False

Question

I am writing a simple program for a homework problem and It seems to be skipping my if statement. I have looked at other questions posed, and the problems there do not seem to b

Answer 1

Replace if i in secretWord == False: with if i not in secretWord

Answer 2

The other answers explain the error in the code well, but you can simplify your code a bit like this:

def isWordGuessed(secretWord, lettersGuessed):
    for i in lettersGuessed or ['_']: # uses ['_'] when lettersGuessed = []
        if not i in secretWord:
            return False
    return True

You can do also do this with a generator expression and all():

def isWordGuessed(secretWord, lettersGuessed):
    return all([i in secretWord for i in lettersGuessed] or [False])

Answer 3

        if i in secretWord == False:

This doesn't do what you think it does. If you want this path to be taken when i isn't in secretWord, you want

        if i not in secretWord:

What you have does a chained comparison. First, it checks

i in secretWord

If that's true, it then checks

secretWord == False

If that's true (which it won't be), it then takes the if path.

Answer 4

Wouldnt it be the same just doing:

``

def isWordGuessed(secretWord, lettersGuessed):

if not lettersGuessed:
    return False
for i in lettersGuessed:
    if i not in secretWord:
        return False
return True

What your doing is called chained comparisons.

Edit: My bad, too late

BR Daniel