Converting Series to Pandas DateTime [duplicate]

Answer 1

I feel better to correct the year first, then convert to datetime:

# identify the year as the last group of digits and prepend 19
corrected_dates = Dae.str.replace('(\d+)$',r'19\1')

# convert to datetime
pd.to_datetime(corrected_dates)

Output:

0   1949-08-10
1   1945-01-21
2   1947-09-15
3   1952-06-13
dtype: datetime64[ns]

Answer 2

from datetime import date
import pandas as pd
from datetime import datetime

Dae = pd.Series(["10Aug49","21Jan45","15Sep47","13Jun52"])
x =[]
new_list = []
for i in Dae:
    i = datetime.strptime(i,"%d%b%y").date()
    if date.today() <= i: 
        i = i.replace(year=i.year - 100)
        new_list.append(i)

print(new_list)


[datetime.date(1949, 8, 10), datetime.date(1945, 1, 21), datetime.date(1947, 9, 15), datetime.date(1952, 6, 13)]