Can't access variables inside parenthesis in bash

Question

In bash, if I run

(foo=14)

And then try to reference that variable later on in my bash script:

echo \"${foo}\"

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Answer 1

Commands enclosed in parenthesis e.g. () are executed in a sub-shell. Any assignment in a sub-shell will not exist outside that sub-shell.

foo=14
bar=$(echo $foo | tr '1' 'a' )
if [[ $? -eq 0 ]]
then
    echo "Setting "'$bar'" was a success. It is ${bar}"
else
    echo "Setting "'$bar'" failed with a nonzero exit code."
fi