How to query for a specific day of the month in Oracle

Question

Trying to automate a query that will pull data for the current month where the day of the month (in the date field) is >= the 15th. Is this possible? If so, what is the syntax t

Answer 1

If your date/time fields are of type timestamp you can do

select x from <your_table>
where EXTRACT(DAY from <timestamp field>) >=15
and EXTRACT(MONTH from <timestamp field>) = EXTRACT(MONTH FROM CURRENT_TIMESTAMP)
and EXTRACT(YEAR from <timestamp field>)  = EXTRACT(YEAR FROM CURRENT_TIMESTAMP);

Answer 2

This will allow you to use any indexes you have on your date_field column:

SELECT *
FROM   table_name
WHERE  date_field >= TRUNC( SYSDATE, 'MM' ) + INTERVAL '14' DAY
AND    date_field <  ADD_MONTHS( TRUNC( SYSDATE, 'MM' ), 1 );

Answer 3

I think what you're after is something like:

with sample_data as (select 1 id, to_date('01/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 2 id, to_date('10/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 3 id, to_date('14/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 4 id, to_date('15/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 5 id, to_date('16/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 6 id, to_date('30/06/2016', 'dd/mm/yyyy') dt from dual union all
                     select 7 id, to_date('01/07/2016', 'dd/mm/yyyy') dt from dual)
select *
from   sample_data
where  dt >= trunc(sysdate, 'mm') + 14
and    dt < last_day(trunc(sysdate)) + 1;

        ID DT        
---------- ----------
         4 15/06/2016
         5 16/06/2016
         6 30/06/2016

(If you wanted rows with any date greater than the 15th of the current month, then remove the last predicate in the where clause.)