Check if string contains single backslashes with regex

Question

I have tried to fix this for a long time, and i just can\'t do it.

It could be any string, but this is an example:

\"\\This string \\contains some\\ bac         


        

Answer 1

Not sure what you're asking.. are you asking how to write a String literal that represents the String you gave as an example? You could either escape the backslash with another backslash, or use triple quotes.

scala> "\\This string \\contains some\\ backslashes\\"
String = \This string \contains some\ backslashes\

scala> """\This string \contains some\ backslashes\"""
String = \This string \contains some\ backslashes\

And replace the backslashes using the same techniques.

scala> "\\This string \\contains some\\ backslashes\\".replace("\\","\\\\")
String = \\This string \\contains some\\ backslashes\\

or

scala> """\This string \contains some\ backslashes\""".replace("""\""","""\\""")
String = \\This string \\contains some\\ backslashes\\

But I have a feeling you want to do something else, like validate input. Maybe you could provide a bit more context?

Answer 2

Try This

val s = """\This string \contains some\ backslashes\"""

s.replaceAll("""\\""","""\\\\""")

Answer 3

It seems you just want to check if a string matches a regex pattern partially, namely, if it contains a literal backslash not preceded nor followed with a backslash.

Use

(?<!\\)\\(?!\\)

See the regex demo.

Sample Scala code:

val s = """"\This string\\ \contains some\ backslashes\""""
val rx = """(?<!\\)\\(?!\\)""".r.unanchored
val ismatch = s match {
  case rx(_*) => true
  case _ => false
}
println(ismatch)

See the Scala online demo.

Note:

• """(?<!\\)\\(?!\\)""".r.unanchored - this line declares a regex object and makes the pattern unanchored, so that no full string match is no longer required by the match block
• Inside match, we use case rx(_*) as there is no capturing group defined inside the pattern itself
• The pattern means: match a backslash (\\) that is not preceded with a backslash ((?<!\\)) and is not followed with a backslash ((?!\\)).