php table: display 3 cells in each row

Question

I looked here: Array into a table with 5 cells in each row

but I cannot adapt my code..

I need to display PHP array results in a table. The table needs to have 3

Answer 1

Try this

echo "<table><tr>";
$num=mysql_numrows($result1);
$i=0;

while ($i < $num)
{
  $aaa=mysql_result   ($result1,$i,"aaa");
  $bbb=mysql_result   ($result1,$i,"bbb");
  if($i %3 ==0)
  {
     echo"</tr><tr><td> $aaa $bbb </td>";  
  }
  else
  {
    echo"<td> $aaa $bbb </td>";  
  }
  $i++;
}
echo "</tr></table>";

Answer 2

use the mod operator % to check for the third element. e.g.

if($i%3 == 0) {
  // this is the third element, start a new tr here
}

Answer 3

To achieve something like this:

You can easily make things configureable by wrapping it into an iterator of it's own that provides rows and columns:

/**
 * function to fetch one row from database
 */
function fetch_row($resultSet = NULL) {
    static $result;
    static $i = 0;
    if ($resultSet) {
        $result = $resultSet;
        return;
    }
    return mysql_fetch_assoc($result);
}

fetch_row($result1); // initialize fetch function

$it = new FetchIterator('fetch_row');

$table = new TableIterator($it, 5);

if ($table->valid()) : ?>

<table border="1">

    <?php foreach ($table as $row => $columns) : ?>

        <tr class="<?php echo $row % 2 ? 'odd' : 'even'; ?>">

            <?php foreach ($columns as $index => $column) : ?>

            <td>
                <?php if ($column) echo $column['aaa'], ' ', $column['bbb']; ?>
            </td>

           <?php endforeach; ?>

        </tr>

    <?php endforeach; ?>

</table>

<?php endif;

Some Demo and see as well Some PHP Iterator Fun.