Regex to validate string for having three non white-space characters

Question

I am using parsley js for validating input and I am using the data-parsley-pattern which allows me to pass in regular expression.

I am trying to validate the string to m

Answer 1

\S{3,}

\S{3,} match any non-white space character [^\r\n\t\f ]

Quantifier: {3,} Between 3 and unlimited times, as many times as possible, giving back as needed [greedy]

e.g. abc or abc def

https://regex101.com/r/gO6sT3/1

---

That, as pointed out by Wiktor Stribiżew, only matches consecutive characters. If you mean "the input can have any number of whitespaces, anywhere, as long as there are at least three non-whitespace characters anywhere" then maybe:

.*\S.*\S.*\S.*

Anything or nothing, non-witespace, anything or nothing, non-whitespace, etc.

e.g. a b c or ab c or abc

https://regex101.com/r/wY0kL4/1

Also see anything and everything at the site: http://www.regular-expressions.info/

Answer 2

"[^\s][^\s][^\s]+"
[] contains a character class.
/s is a whitespace character.
^ works kind of like a logical not.
The + catches one or more of the previous character
You may need to add more backslashes depending on any special escape characters