Getting certain columns in bash

Question

Suppose I have an array where each element in the array is in the following format:

someText (x1,y1,z1) (x2,y2,z2) (x3,y2,z3) KEY

What is the a

Answer 1

This is how you can get first and last element of your string in the array:

echo "someText (x1,y1,z1) (x2,y2,z2) (x3,y2,z3) KEY" | rev | cut -d " " -f 1 | rev

echo "someText (x1,y1,z1) (x2,y2,z2) (x3,y2,z3) KEY" | cut -d " " -f 1

Answer 2

You can do something like this (where OLDARRAY is the previous array and NEWARRAY is the new one).

NEWARRAY=()
for I in "${!OLDARRAY[@]}"; do
    IFS=$' ' read -ra T <<< "${OLDARRAY[I]}"
    NEWARRAY[I]="${T[0]} ${T[@]:(-1)}"
done

Example output:

> set | grep ^NEWARRAY
NEWARRAY=([0]="someText KEY" [1]="someText2 KEY2")

Answer 3

echo "someText (x1,y1,z1) (x2,y2,z2) (x3,y2,z3) KEY"|awk '{print $1,$NF}'