Print line if contains word

Question

I am trying to make a batch file to execute a few things for me.
Now I do understand a few programming languages, but I haven\'t done much in batch file programming yet.

Answer 1

If you simply want to output the matching line with no logic checking, do

findstr /i "node" "%file1%"

If you want to execute some code if the line is found, use conditional execution.

findstr /i "node" "%file1%" && (

    rem File contained "node".  Do some stuff.

) || (

    rem File did not contain "node".  Do something else.

)

And if you want to use findstr to test for the existence of a string without actually dumping the result to the console, simply add >NUL either before or after the findstr command.

>NUL findstr /i "node" "%file1%" && (success) || fail

Answer 2

If you are new to scripting, I would avoid batch (shell script) and use PowerShell. PowerShell is far more powerful and flexible.

get-content 'file.txt' | select-string 'node:(\s+)' | foreach-object {
  $_.Matches[0].Groups[1].Value
}

This command would output the first substring match (from inside parentheses in regular expression) from each line.