Find text javascript

Question

I Have string random length

Ex:

 sadsadsadsad(323213)dfsssds

 sadsadsadsad(321)dfsssds

How can I find the values in brackets?.

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Answer 1

Try This:

var str =  'sadsadsadsad(321)dfss888s(120)ds';

str.match(/\(\d+\)/g).map ( value => { console.log( value.replace(/[)(]/g, '') ) } );

Answer 2

You could catch the group within () using replace(), and passing it to a callback function that push it into an array.

var str = 'sadsadsadsad(323213)dfsssds(1234)dfsssds(4567)dfsssds(abcf)';

var arr = [];

str.replace(/\(([a-z0-9]*)\)+/gi, (a,b)=>arr.push(b));

console.log(arr);

Answer 3

var str = "sadsadsadsad(323213)dfsssds"; 
var val= str.match(/\((.*?)\)/);
if (val) {
    console.log("found");
 }

You can use Regex

var str = "sadsadsadsad(323213)dfsssds"; 
var val= str.match(/\((.*?)\)/);
if (val) {
    console.log("found");
 }

Answer 4

You can use lastIndexOf and substring

var text = "sadsadsadsad(323213)dfsssds";
var newText = text.substring(text.lastIndexOf("(") + 1, text.lastIndexOf(")"));

console.log(newText)

Answer 5

You can use indexOf and substring

let str = 'sadsadsadsad(321)dfsssds';

let getFirstIndex = str.indexOf('(');
let getSecondIndex = str.indexOf(')');

let subStr = str.substring(getFirstIndex + 1, getSecondIndex);
console.log(subStr)

Answer 6

Try regex /\(.*\)/

function getValue(s) {
    var strs = s.match(/\(.*?\)/g);
    if (strs == null) {
        return '';
    }
    return strs.map(str=>str.replace(/[()]/g, ''));
    //return strs.join(' ,').replace(/[()]/g, '')
}



console.log(getValue('sadsadsadsad(323213)dfsssds(abc)'));
console.log(getValue('sadsad(_d_)sadsad(321)dfsssds'));
console.log(getValue('sadsad(33)sadsad(321dfsssds'));